Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60...........

[Max@Math Revolution]

Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60 than she was buying before the increase. What was the initial price per liter of milk?

(A) $2.00
(B) $2.50
(C) $2.75
(D) $3.00
(E) $3.50

[Max@Math Revolution]

Solution: The price of milk is increased by 20%.

Let the original price of milk per liter be $10.

Increased price: \(\frac{120}{100}\) * $10 = $12[/m]

Number of liters of milk: \(\frac{Total\ price\ }{price\ per\ litre}\)

Number of liters of milk before increase: \(\frac{60}{10}\)=6

Number of liters of milk after increase: \(\frac{60}{12}\)=5

The difference in the quantity of milk obtained: 6 - 5 = 1

Thus, for the $10 initial price, the difference is 1 liter.

For 5 liters difference, \(\frac{10}{5}\) = $2

Therefore, A is the correct answer.

Answer A

[Scott@TargetTestPrep]

Que: With the increase of 20% in the price of milk, a housewife can buy 5 liters less quantity for $60 than she was buying before the increase. What was the initial price per liter of milk?

(A) $2.00
(B) $2.50
(C) $2.75
(D) $3.00
(E) $3.50

Solution:

We can let p be the initial price per liter of the milk and create the equation:

60/(1.2p) = 60/p - 5

50/p = 60/p - 5

50 = 60 - 5p

5p = 10

p = 2

Answer: A