In the given figure, \(BD\) is the median of triangle \(ABC\) and the lines \(BD\) and \(CE\) intersect ...

[Gmat_mission]

In the given figure, \(BD\) is the median of triangle \(ABC\) and the lines \(BD\) and \(CE\) intersect at point \(F.\) If the area of triangle \(BFC\) is \(6\,\text{cm}^2\) and area of the quadrilateral \(FEAD\) is \(18\,\text{cm}^2.\) Find the area of triangle \(FDC,\) if the ratio of the area of triangle \(FDC\) and triangle \(FEB\) is \(3:2.\)

a. \(12\,\text{cm}^2\)
b. \(18\,\text{cm}^2\)
c. \(24\,\text{cm}^2\)
d. \(36\,\text{cm}^2\)
e. \(42\,\text{cm}^2\)

Answer: D

Source: e-GMAT