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In the given figure, \(BD\) is the median of triangle \(ABC\) and the lines \(BD\) and \(CE\) intersect at point \(F.\) If the area of triangle \(BFC\) is \(6\,\text{cm}^2\) and area of the quadrilateral \(FEAD\) is \(18\,\text{cm}^2.\) Find the area of triangle \(FDC,\) if the ratio of the area of triangle \(FDC\) and triangle \(FEB\) is \(3:2.\)
a. \(12\,\text{cm}^2\)
b. \(18\,\text{cm}^2\)
c. \(24\,\text{cm}^2\)
d. \(36\,\text{cm}^2\)
e. \(42\,\text{cm}^2\)
Answer: D
Source: e-GMAT
a. \(12\,\text{cm}^2\)
b. \(18\,\text{cm}^2\)
c. \(24\,\text{cm}^2\)
d. \(36\,\text{cm}^2\)
e. \(42\,\text{cm}^2\)
Answer: D
Source: e-GMAT
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