There are enough available spaces on a school team to select at most 1/3 o

[BTGModeratorVI]

There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?

(A) 16
(B) 17
(C) 33
(D) 34
(E) 35

Answer: D
Source: Manhattan prep

[Scott@TargetTestPrep]

There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?

(A) 16
(B) 17
(C) 33
(D) 34
(E) 35

Answer: D

Solution:

To fill the space on the team, a maximum of 16 people could be selected, so 50 - 16 = 34 can be rejected while still filling all available spaces.

Answer: D

[Brent@GMATPrepNow]

There are enough available spaces on a school team to select at most 1/3 of the 50 students trying out for the team. What is the greatest number of students that could be rejected while still filling all available spaces for the team?

(A) 16
(B) 17
(C) 33
(D) 34
(E) 35

Answer: D
Source: Manhattan prep

1/3 of 50 = (1/3)(50) = 50/3 = 16 2/3
Since the number of available spaces cannot be greater than 16 2/3, there must be 16 available spaces.
So, 16 students (among the original 50 students) can be selected to join the team, which means the other 34 students must be rejected.

Answer: D

Cheers,
Brent