What is the remainder when n is divided by 26, given that n divided by 13 gives “a” as the quotient and “b” as the remai

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What is the remainder when n is divided by 26, given that n divided by 13 gives “a” as the quotient and “b” as the remainder? (a, b and n are positive integers)

(1) a is odd
(2) b = 3

Answer: C
Source: Veritas Prep
Source: — Data Sufficiency |

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Given that n divided by 13 = a remainder b
The quotient remainder theorem says that if n divided by d equals q with remainder r, then n = dq+r
In relation to information in the question stem, n = 13a + b and we are to find the remainder of 13a+b/26

Statement 1 => a is odd
This does not give any information about the value of b so statement 1 is NOT SUFFICIENT

Statement 2 => b = 3
This does not give any information about the value of a so statement 2 is NOT SUFFICIENT

Combining both statements together =>
From statement 1 =>
a is odd
From statement 2 => b = 3
Odd numbers are of the form 2k + 1
So, n = 13(2k + 1) + 3 = 26k + 13 + 3
= 26k + 16
n = multiple of 26 + 16 so when n is divided by 26, the remainder is 16

Both statements combined together ARE SUFFICIENT
Answer = C

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BTGModeratorVI wrote:
Wed Jan 06, 2021 8:04 am
What is the remainder when n is divided by 26, given that n divided by 13 gives “a” as the quotient and “b” as the remainder? (a, b and n are positive integers)

(1) a is odd
(2) b = 3

Answer: C
Source: Veritas Prep
Target question: What is the remainder when n is divided by 26

Given: n divided by 13 gives “a” as the quotient and “b” as the remainder? (a, b and n are positive integers)
There's a nice rule that say, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2

So, we can taken the given information and write: n = 13a + b

Statement 1: a is odd
There's no information about b, so it will be impossible to determine the remainder when divided by 26.
Consider these two cases:
Case a: a = 1 and b = 2. In this case, n = (13)(1) + 2 = 15, so n divided by 26 leaves a remainder of 15
Case b: a = 1 and b = 3. In this case, n = (13)(1) + 3 = 16, so n divided by 26 leaves a remainder of 16
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: b = 3
Consider these two contradictory cases:
Case a: a = 2 and b = 3. In this case, n = (13)(2) + 3 = 29, so n divided by 26 leaves a remainder of 3
Case b: a = 1 and b = 3. In this case, n = (13)(1) + 3 = 16, so n divided by 26 leaves a remainder of 16
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that a is odd, which means a = 2k + 1 for some integer k
Statement 2 tells us that b = 3

So, let's take the given information (n = 13a + b) and replace a with 2k + 1 and replace b with 3 to get:
n = 13(2k + 1) + 3
= 26k + 13 + 3
= 26k + 16
Here we can see that n is 16 greater than some multiple of 26, so when we divide n by 26, the remainder will be 16
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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