Inequalities

[beater]

Is 2y>3z?

1. 3y > 2z
2. y < 2z

Is there a way to solve this using transitive properties?

[gace780]

2y>3z same as 6y>9z

A:
===
3y>2z ===> 6y > 4z

B:
===
y<2z ====> 6y <12z

Both together 4z < 6y <12z

Therefore, 6y may or may not be greater than 9z. Answer is E!

[gmat009]

IMO A
What's OA

[namitrajiv]

should be E
We need to find if y>1.5 z
first statement says y>0.66 Z , clearly insufficient because if y >0.66 z it can or cannot be greater than 1.5 z

2nd statement says y<2z, again insufficient because if y <2z it can or cannot be greater than 1.5 z

combined 0.66z<y<2z
again y can be greater than or less than 1.5 z , possible values of y are
1.2 z(<1.5z), 1.7z(>1.5z)

[gmat009]

should be E
We need to find if y>1.5 z
first statement says y>0.66 Z , clearly insufficient because if y >0.66 z it can or cannot be greater than 1.5 z

2nd statement says y<2z, again insufficient because if y <2z it can or cannot be greater than 1.5 z

combined 0.66z<y<2z
again y can be greater than or less than 1.5 z , possible values of y are
1.2 z(<1.5z), 1.7z(>1.5z)

Yes you are right....
By mistake I understood in a wrong way.