In order for a nursery to meet the conditions of its insurance there must be at least one adult present for every 4

This topic has expert replies
Moderator
Posts: 7187
Joined: Thu Sep 07, 2017 4:43 pm
Followed by:23 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

In order for a nursery to meet the conditions of its insurance there must be at least one adult present for every 4 children. The total number of children and adults at the nursery is 24. Is the nursery meeting the terms of its insurance?

(1) The difference between the number of children and the number of adults is smaller than 15

(2) If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3


OA D

Source: Magoosh
Source: — Data Sufficiency |

Legendary Member
Posts: 2499
Joined: Sun Oct 29, 2017 2:04 pm
Followed by:6 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:
Mon Nov 16, 2020 5:54 pm
In order for a nursery to meet the conditions of its insurance, there must be at least one adult present for every 4 children. The total number of children and adults at the nursery is 24. Is the nursery meeting the terms of its insurance?

(1) The difference between the number of children and the number of adults is smaller than 15

(2) If one more adult arrives at the nursery and one child is picked up by their parents, the ratio of adults to children will be 1:3


OA D

Source: Magoosh
From the question, we know that \(C + A = 24\)

Statement 1:
\(C - A < 15\)
\(\Rightarrow\) Maximum \(C - A = 14\)
Solving for this, we get \(C = 19\) and \(A = 5\)
So, the maximum value of \(\dfrac{C}{A}\) is \(3.8\). Sufficient \(\Large{\color{green}\checkmark}\)

Statement 2:
\(\dfrac{C - 1}{A + 1} = \dfrac{1}{3}\)
Solving the equation we get \(\dfrac{C}{A} = 3.8\). Sufficient \(\Large{\color{green}\checkmark}\)

Therefore, D