In a population of 100,000 males, 80% can be expected to live to age 60 and 60% can be expected to live to 80. Given

[BTGmoderatorDC]

In a population of 100,000 males, 80% can be expected to live to age 60 and 60% can be expected to live to 80. Given that a male in this group is 60, what is the probability that he lives to 80?

A. 48%
B. 60%
C. 75%
D. 78%
E. 80%



OA C

Source: Veritas Prep

[swerve]

In a population of 100,000 males, 80% can be expected to live to age 60 and 60% can be expected to live to 80. Given that a male in this group is 60, what is the probability that he lives to 80?

A. 48%
B. 60%
C. 75%
D. 78%
E. 80%



OA C

Source: Veritas Prep

\(P(a) = 80\%\) of the \(100,000\) males, \(80,000\) males, can be expected to live to \(60\)- but

\(P(b) = 60\%\) of \(100,000\) males, \(60,000\) males can be expected to live to \(80\)

\(b\) is a subset of a so \(\dfrac{60,000}{80,000} \cdot 100 = 75\%\Longrightarrow\)C

[Scott@TargetTestPrep]

In a population of 100,000 males, 80% can be expected to live to age 60 and 60% can be expected to live to 80. Given that a male in this group is 60, what is the probability that he lives to 80?

A. 48%
B. 60%
C. 75%
D. 78%
E. 80%



OA C

Solution:

Since 80% and 60% are expected to live to ages 60 and 80, respectively, 80,000 and 60,000 males are expected to live to ages 60 and 80, respectively. Thus, the probability that a male lives to age 80, given that he is 60, is:

60,000/80,000 = 3/4 = 75%

Answer: C