A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downst

[BTGModeratorVI]

A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at an average speed of (v+3) miles per hour. If the trip upstream took a half hour longer than the trip downstream, then how many hours did it take the boat to travel downstream?

A. 2.5
B. 2.4
C. 2.3
D. 2.2
E. 2.1

Answer: A
Source: Official guide

[Brent@GMATPrepNow]

A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at an average speed of (v+3) miles per hour. If the trip upstream took a half hour longer than the trip downstream, then how many hours did it take the boat to travel downstream?

A. 2.5
B. 2.4
C. 2.3
D. 2.2
E. 2.1

Answer: A
Source: Official guide

I like to begin with a "word equation."
We can write:
travel time upstream = travel time downstream + 1/2

Time = distance/rate
So, we can replace elements in our word equation to get:
90/(v-3) = 90/(v+3) + 1/2

Now solve for v (lots of work here)
.
.
.
v = 33

So, travel time downstream = 90/(v+3)
= 90/(33+3)
= 90/36
= 5/2
= 2 1/2 hours
Answer: A

Cheers,
Brent

[swerve]

A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at an average speed of (v+3) miles per hour. If the trip upstream took a half hour longer than the trip downstream, then how many hours did it take the boat to travel downstream?

A. 2.5
B. 2.4
C. 2.3
D. 2.2
E. 2.1

Answer: A
Source: Official guide

Here we go,

\(\dfrac{90}{v-3}=90(v+3)+0.5\)

\(\dfrac{90(v+3-v+3)}{v^2-9}=0.5\)

\(\dfrac{90\cdot 6}{v^2-9}=0.5\)

\(90 \cdot 12+9=v^2\)

\(v^2=1089\)

\(v=33\)

Therefore, \(v+3=36\)

Hence, the total time required to travel downstream \(=\dfrac{90}{36}=2.5\) hours

[Scott@TargetTestPrep]

A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at an average speed of (v+3) miles per hour. If the trip upstream took a half hour longer than the trip downstream, then how many hours did it take the boat to travel downstream?

A. 2.5
B. 2.4
C. 2.3
D. 2.2
E. 2.1

Answer: A
Source: Official guide

Solution:

Since time = distance/rate, the time going upstream = 90/(v – 3) and the time going downstream = 90/(v + 3). Since the time going upstream is ½ hour more than the time going downstream, we add ½ hour to the downstream trip to make the two times equal, and then we can set up an equation as follows:

90/(v - 3) = 90/(v + 3) + 1/2

Let’s multiply the equation by 2(v - 3)(v + 3) to eliminate the denominators:

2(90)(v + 3) = 2(90)(v - 3) + (v - 3)(v + 3)

180v + 540 = 180v - 540 + v^2 - 9

540 = v^2 - 549

v^2 = 1089

v = √1089

v = 33

Since the time going downstream = 90 / (v + 3), and v = 33, the time going downstream = 90 / (33 + 3) = 90/36 = 5/2 = 2.5 hours.

Answer: A

[Scott@TargetTestPrep]

A boat traveled upstream 90 miles at an average speed of (v-3) miles per hour and then traveled the same distance downstream at an average speed of (v+3) miles per hour. If the trip upstream took a half hour longer than the trip downstream, then how many hours did it take the boat to travel downstream?

A. 2.5
B. 2.4
C. 2.3
D. 2.2
E. 2.1

Answer: A
Source: Official guide

Solution:

Since time = distance/rate, we have:

Upstream Time = Downstream Time + 0.5

90/(v - 3) = 90/(v + 3) + 0.5

Multiplying the equation by 2(v - 3)(v + 3), we have:

180(v + 3) = 180(v - 3) + (v - 3)(v + 3)

180v + 540 = 180v - 540 + v^2 - 9

1089 = v^2

33 = v

Therefore, the downstream time is 90/(33 + 3) = 2.5 hours.

Answer: A