How many integers are there between, but not including, integers r and s ?

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BTGModeratorVI wrote:
Fri Aug 14, 2020 1:16 pm
How many integers are there between, but not including, integers r and s ?

(1) s-r=10
(2) There are 9 integers between, but not including, r + 1 and s + 1.

Answer: D
Source: Official guide
Target question: How many integers are there between, but not including, integers r and s ?

Statement 1: s - r = 10
First of all, this tells us that s is greater than r
So, on the number line, we have: ------r------------s----

Also notice that, if we take the given equation and add r to both sides, we get s = r+10
So, we can replace s with r+10 to get: ------r------------(r+10)----

Since r is an integer, we know that r+1 is an integer, and r+2 is an integer, and r+3 is an integer, etc.
If we add all of these values to our number line we get: ------r--(r+1)--(r+2)--(r+3)--(r+4)--(r+5)--(r+6)--(r+7)--(r+8)--(r+9)--(r+10)----
We can see that there are 9 integers between r and s
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: There are 9 integers between, but not including, r + 1 and s + 1.
The key here is to recognize that the number of integers between r + 1 and s + 1 IS THE SAME AS the number of integers between r and s

For example, we know that there are three integers between 5 and 9 (the integers are 6, 7 and 8)
If we add one to 5 and 9, we get 6 and 10
Notice that there are also three integers between 6 and 10 (the integers are 7, 8 and 9)

So, if there are 9 integers between r + 1 and s + 1, then we can also conclude that there are 9 integers between r and s
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: D

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BTGModeratorVI wrote:
Fri Aug 14, 2020 1:16 pm
How many integers are there between, but not including, integers r and s ?

(1) s-r=10
(2) There are 9 integers between, but not including, r + 1 and s + 1.

Answer: D
Source: Official guide
Statement 1

\(s=r+10\)

So, basically the numbers we have are \(r,r+1,r+2,r+3,r+4,r+5,r+6,r+7,r+8,r+9,r+10( r+10 is S)\)

So, there are 9 integers in between another way to solve would be \(s-r+1 = 10+1 = 11\) total number of integers since we need the numbers in between \(11 - 2\) ( the 2 numbers we subtract are r and s) hence we get 9. \(\Large{\color{green}\checkmark}\)

Statement 2

There are 9 integers so we have a total of 11 integers at the moment.

\(s+1 - (r+1) + 1 = 11\)
\(s+1-r-1=10\)
\(s-r=10\) which is same as statement 1. \(\Large{\color{green}\checkmark}\)

So, the correct answer is D