BTGmoderatorDC wrote: ↑Tue Jul 14, 2020 7:30 pm
The units digit of (44^91)*(73^37) is:
(A) 2
(B) 4
(C) 6
(D) 8
(E) 0
OA
A
Source: Magoosh
To know the units digit of (44^91)*(73^37), we must the units digit of (4^91)*(3^37).
Let's understand the power cycle of 4 and 3.
4:
• 4^1 = 4 => unit digit = 4;
• 4^2 = 16 => unit digit = 6;
• 4^3 = 64 => unit digit = 4;
• 4^4 = 216 => unit digit = 6;
You will note that if the exponent of 4 is odd, the unit digit is 4 and if the exponent is even, the unit digit is 6.
Thus, the unit digit if (44)^91 = 4.
3:
• 3^1 = 3 => unit digit = 3;
• 3^2 = 9 => unit digit = 9;
• 3^3 = 27 => unit digit = 7;
• 3^4 = 81 => unit digit = 1;
• 3^5 = 243 => unit digit = 3;
You will note that after every 4 consecutive exponents, the units digit of the exponent of 3 repeats. They are in order 3, 9, 7 and 1.
Let's find out the units digit of 3^37.
3^37 can be written as 3^(36 + 1) = 3^(4*9 + 1)
So, the units digit of 3^37 = the units digit of 3^1 = 3
Thus, the units digit of (44^91)*(73^37) = units digit of 4*3 = units digit of 12 = 2.
Correct answer:
A
Hope this helps!
-Jay
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