VJesus12 wrote: ↑Tue Jun 30, 2020 7:54 am
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
(A) 1/2
(B) 2/5
(C) 3/5
(D) 4/5
(E) 5/8
[spoiler]OA=E[/spoiler]
Source: Official Guide
Solution:
We are given that the night crew loaded 3/4 as many boxes as each worker on the day crew and that the night crew has 4/5 as many workers as the day crew.
4/5(number of day workers) = number of night workers
Let's choose the convenient value of 20 for the number of day workers and substitute it into the equation above:
4/5 x 20 = number of night workers
16 = number of night workers
Next, we set up the equation for the number of boxes loaded by each worker.
(¾) x (number of boxes loaded by each day worker) = number of boxes loaded by each night worker
Now let's choose the convenient value of 8 for the number of boxes loaded by each day worker and substitute it into the above equation:
¾ x 8 = number of boxes loaded by each night worker
6 = number of boxes loaded by each night worker
Thus, the total number of boxes loaded by each type of worker is as follows:
Day workers = 20 x 8 = 160
Night workers = 16 x 6 = 96
Total boxes loaded = 160 + 96 = 256
The question asks us to determine the fraction of all the boxes loaded by the day crew, and that is:
(Total boxes loaded by day crew)/(Total boxes loaded)
160/256 = 40/64 = 5/8
Answer: E