If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume of

[M7MBA]

If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume of cube \(Y\) to the volume of cube \(X?\)

(A) 1/2
(B) 1/4
(C) 1/6
(D) 1/8
(E) 1/27

[spoiler]OA=D[/spoiler]

Source: Official Guide

[anonylfc]

Area of cube = (side)^3

As side of X is twice of Y-> X=2Y

Ratio of cube Y to cube X will be
=Y^3/X^3
=Y^3/ (2Y)^3
=Y^3/ 8Y^3
=1/8
Hope this helps. Please upvote if you found this helpful !

[Scott@TargetTestPrep]

If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume of cube \(Y\) to the volume of cube \(X?\)

(A) 1/2
(B) 1/4
(C) 1/6
(D) 1/8
(E) 1/27

[spoiler]OA=D[/spoiler]

Source: Official Guide

Solution:

Let y = the edge length of cube Y. Thus, 2y = the edge length of cube X. The volume of cube Y is therefore y^3, and that of cube X is (2y)^3 = 8y^3. So the ratio of the volume of cube Y to that of cube X is x^3 / (8x^3) = 1/8.

Answer: D