Canceling out 5! from the numerator and denominator, we have:
(12 x 11 x 10 x 9 x 8 x 7 x 6) / (3^4 x 2^6)
(2^2 x 3 x 11 x 2 x 5 x 3^2 x 2^3 x 7 x 2 x 3) / (3^4 x 2^6)
(2^7 x 3^4 x 5 x 7 x 11) / (3^4 x 2^6)
2 x 5 x 7 x 11
10 x 77
770
Answer: B
\(\dfrac{12!}{3^4\cdot 5!\cdot 2^6}=\)
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(12 x 11 x 10 x 9 x 8 x 7 x 6) / (3^4 x 2^6)
(2^2 x 3 x 11 x 2 x 5 x 3^2 x 2^3 x 7 x 2 x 3) / (3^4 x 2^6)
(2^7 x 3^4 x 5 x 7 x 11) / (3^4 x 2^6)
2 x 5 x 7 x 11
10 x 77
770
Answer: B
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