What is the value of \((x - y)^4?\)

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What is the value of \((x - y)^4?\)

by M7MBA » Sun Apr 26, 2020 9:14 am

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What is the value of \((x - y)^4?\)

(1) The product of \(x\) and \(y\) is \(7.\)
(2) \(x\) and \(y\) are integers

[spoiler]OA=C[/spoiler]

Source: Manhattan GMAT
Source: — Data Sufficiency |

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M7MBA wrote:
Sun Apr 26, 2020 9:14 am
What is the value of \((x - y)^4?\)

(1) The product of \(x\) and \(y\) is \(7.\)
(2) \(x\) and \(y\) are integers

[spoiler]OA=C[/spoiler]

Source: Manhattan GMAT
Let's take each statement one by one.

(1) The product of \(x\) and \(y\) is \(7.\)

Certainly insufficient as x and y can take any values.

(2) \(x\) and \(y\) are integers.

Certainly insufficient as values for x and y are not given.

(1) and (2) together

Given that xy = 7 and x and y are integers, one of x and y is ±1 and the other is ±7.

Case 1: Say x = 1 and y = 7; thus, \((x - y)^4=(1-7)^4=6^4\); since the exponent (= 4) is even.
Case 2: Say x = 7 and y = 1; thus, \((x - y)^4=(7-1)^4=6^4\)
Case 3: Say x = –1 and y = –7; thus, \((x - y)^4=(–1+7)^4=6^4\)
Case 4: Say x = –7 and y = –1; thus, \((x - y)^4=(-7+1)^4=6^4\); since the exponent (= 4) is even.

We have a unique value of \((x - y)^4=6^4\). Sufficient.

The correct answer: C

Hope this helps!

-Jay
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