A certain liquid passes through a drain at a rate of w/20 gallons every x seconds...

[AAPL]

Princeton Review

A certain liquid passes through a drain at a rate of w/20 gallons every x seconds. At that rate, how many minutes will it take y gallons to pass through the drain?

A. y/(1200xy)
B. 20xy/w
C. xy/(3w)
D. w/(3xy)
E. 3y/(wx)

OA C

[Jay@ManhattanReview]

Princeton Review

A certain liquid passes through a drain at a rate of w/20 gallons every x seconds. At that rate, how many minutes will it take y gallons to pass through the drain?

A. y/(1200xy)
B. 20xy/w
C. xy/(3w)
D. w/(3xy)
E. 3y/(wx)

OA C

Given that the liquid passes through at a rate of w/20 gallons every x seconds, we have the liquid passes through at a rate of w/(20x) gallons per second

Or, the liquid passes through at a rate of (60w)/(20x) = 3w/x gallons per minute

Thus, it will take y/(3w/x) = xy/3w minutes

The correct answer: C

Hope this helps!

-Jay
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[Scott@TargetTestPrep]

Princeton Review

A certain liquid passes through a drain at a rate of w/20 gallons every x seconds. At that rate, how many minutes will it take y gallons to pass through the drain?

A. y/(1200xy)
B. 20xy/w
C. xy/(3w)
D. w/(3xy)
E. 3y/(wx)

OA C

The rate is (w/20)/x = w/(20x) gal/sec.

So y gallons will pass through the drain in y/(w/(20x)) = 20xy/w seconds, which is (20xy/w)/60 = 20xy/(60w) = xy/(3w) minutes

Answer: C