On this year's Westchester basketball team, the players are all either 5, 7, or 11 years of age...

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Princeton Review

On this year's, Westchester basketball team, the players are all either 5, 7, or 11 years of age. If the product of the ages of the players on the team is 18,865, then what is the probability that a randomly selected team member will not be 7?

A. 3/7
B. 2/5
C. 16/37
D. 3/5
E. 49/55

OA B

[Jay@ManhattanReview]

Princeton Review

On this year's, Westchester basketball team, the players are all either 5, 7, or 11 years of age. If the product of the ages of the players on the team is 18,865, then what is the probability that a randomly selected team member will not be 7?

A. 3/7
B. 2/5
C. 16/37
D. 3/5
E. 49/55

OA B

Let's factorize 18,865.

18,865 = 5*7^3*11 = 5^1 * 7^2 * 11 ^1;

So, there are 1 + 2 + 1 = 5 players; out of these 7, two players are not 7 years old.

Thus, the probability that a randomly selected team member will not be 7 = 2/5.

The correct answer: B

Hope this helps!

-Jay
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Manhattan Review

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[Scott@TargetTestPrep]

Princeton Review

On this year's, Westchester basketball team, the players are all either 5, 7, or 11 years of age. If the product of the ages of the players on the team is 18,865, then what is the probability that a randomly selected team member will not be 7?

A. 3/7
B. 2/5
C. 16/37
D. 3/5
E. 49/55

OA B

Let’s prime factorize 18,865

18,865 = 5 x 3773 = 5 x 11 x 343 = 5 x 11 x 7 x 7 x 7

We see that there are a total of 5 players, and 3 of them are 7 years old, and 2 of them are not. So the probability that a randomly selected player will not be 7 is 2/5.

Answer: B