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Combination / Permutation problem

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Combination / Permutation problem

by jessicamuniz » Sat Nov 22, 2008 12:27 pm
Hi everybody, here is a questions. I got the answer but I would like to know your options. Thanks in advance.

Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stoked with 3 types of balls and 6 types of board games, how many different selections of the items can Amanda make?
a. 9 b.12 c.14 d.15 e.60
ANS: E
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by Tryingmybest » Sat Nov 22, 2008 12:29 pm
Ans 60

3C1 * 6C3 = 60
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by Abdulla » Sat Nov 22, 2008 8:12 pm
Tryingmybest wrote:Ans 60

3C1 * 6C3 = 60
What is the meaning of C ( 3C1) ?
Abdulla
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by hrishikesh05 » Sat Nov 22, 2008 10:16 pm
C is the notation for combination


Check this link for more information on C

https://en.wikipedia.org/wiki/Mathematical_combination
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by Abdulla » Sat Nov 22, 2008 11:18 pm
Thanks bro
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by Jeff@TargetTestPrep » Mon Jan 08, 2018 11:41 am
jessicamuniz wrote:Amanda goes to the toy store to buy 1 ball and 3 different board games. If the toy store is stoked with 3 types of balls and 6 types of board games, how many different selections of the items can Amanda make?
a. 9
b.12
c.14
d.15
e.60
Amanda can select a ball in 3C1 = 3 ways and she can selected a board game in 6C3 = 6!/[3!(6-3)!] = (6 x 5 x 4)/3! = (6 x 5 x 4)/(3 x 2 x 1) = 20. So, the total number of ways is 3 x 20 = 60.

Answer: E

Jeffrey Miller
Head of GMAT Instruction
[email protected]

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