jjjinapinch wrote: ↑Wed Aug 02, 2017 10:44 am
If x = 2t and y = t/3, what is the value of x^2 - y^2?
(1) t^2 - 3 = 6.
(2) t^3 = -27
Official Guide question
Answer:
D
Solution:
We need to determine the value of x^2 - y^2 given that x = 2t and y = t/3. Substituting 2t for x and t/3 for y, we have:
(2t)^2 - (t/3)^2 = 4t^2 - t^2/9 = 35t^2 / 9
Therefore, if we can determine the value of t, we can determine the value of x^2 - y^2 since it’s equal to 35t^2 / 9.
Statement One Alone:
Solving the equation, we have:
t^2 = 9
t = ±√9
t = ±3
Although the value of t is not unique (it can be either 3 or -3), we see that t^2 = 9, regardless of whether t is 3 or -3. Thus, the value of x^2 - y^2 is 35(9) / 9 = 35. Statement one alone is sufficient.
Statement Two Alone:
Solving the equation, we have:
t^3 = -27
t = ∛(-27)
t = -3
Since t = -3, the value of x^2 - y^2 is [35(-3)^2]/9 = 35(9)/35 = 35. Statement two alone is sufficient.
Answer: D