Does the area of a certain square greater than

[NandishSS]

Does the area of a certain square greater than the area of a certain rectangle?

(1) One side of the rectangle equals to the side of the square.

(2) One side of the rectangle is twice greater than the side of the square.

OA:C

[melguy]

Statement 1

Square = 10 x 10 = 100
Rectangle = 10 x 5 = 50
or
Square = 10 x 10 = 100
Rectangle = 10 x 20 = 200

Not Sufficient

Statement 2

Square = 10 x 10 = 100
Rectangle = 20 x 1 = 20
or
Square = 10 x 10 = 100
Rectangle = 20 x 15 = 300

Not Sufficient

Combine

1 side is equal = 10 (for both)
1 side of the rectangle is twice the square (i.e. square = 10, Rectangle = 20)

We can say with certainty that the area of rectangle will be greater.

Answer is C

[Jay@ManhattanReview]

Nandish,

A square can be called a special rectangle having equal length and breadth.

This question can be solved logically.

We know that the area of a rectangle = Length (a) * Breadth (b) = a*b

Clearly, statement 1 is insufficient as the area of the square = a^2. We cannot compare a^2 and a*b as we have no information about b.

Similarly, statement 2 is insufficient as we do not have any information about the other side of the rectangle: it may be equal to, greater than or smaller than that of the square, resulting in all possible results: Area is equal, more, and less.

However, combining both the statements will result in a unique answer.

Area of square = a^2;

Area of rectangle = a*(2a) = 2a^2 > a^2.

The answer is a unique 'NO'. OA C

Hope this helps!

--Jay

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