BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

tough DS Question(Speed Question)

Expert replies
by aj_gmatwizard » Thu May 21, 2015 7:20 am
Rachel drove the 120 miles from A to B at a constant speed. What was this speed?

Statement #1: If she had driven 50% faster, her new time would have been 2/3 of her original time.

Statement #2: If she had driven 20 mph faster, she would have arrived an hour sooner.

Answer:
Rachel drove the 120 miles from A to B at a constant speed. What was this speed?

Let's say the original variables are D = 120, R, and T, and the original case is 120 = RT.

Statement #1: If she had driven 50% faster, her new time would have by 2/3 of her original time.

To increase by 50%, we will multiply by the multiplier 1.5. This means that the new speed, R2, is R2 = 1.50*R = (3/2)*R. The new time is T2 = (2/3)*T. Well, we know, that 120 = (R2)*(T2) --- the new speed and time must have the small product as the original speed and time. 120 = (R2)*(T2) = [(3/2)*R]*[(2/3)*T] = (3/2)*(2/3)*RT = RT. This information leads in a big logical circle right back to the original equation 120 = RT. It gives us no new information at all. Therefore, this statement, by itself, does not provide any insight into the answer to the prompt question. This statement is insufficient.

Statement #2: If she drove 20 mph faster, she would have arrived an hour sooner.

Now, we know R2 = R + 20 and T2 = T - 1. Again, we know that 120 = (R2)*(T2), so

120 = (R + 20)*(T - 1) = RT - R + 20T - 20

120 - RT = 0 = 20T - R - 20

That is one equation with two unknowns, and 120 = RT is a second equation with two unknowns. We have two clearly different equations for the two unknowns, so even without solving, this is sufficient to determine a unique value for the variables R & T.

Answer = (B)

I don't understand the second part. we cant solve the equations 120=RT and 120-RT=0=20T-R-20

20T-R=20 this just 1 equation and two unknowns[/b]
Join the discussion
Source: — Data Sufficiency |

by GMATGuruNY » Thu May 21, 2015 7:40 am
aj_gmatwizard wrote:Rachel drove the 120 miles from A to B at a constant speed. What was this speed?

Statement #1: If she had driven 50% faster, her new time would have been 2/3 of her original time.

Statement #2: If she had driven 20 mph faster, she would have arrived an hour sooner.
Statement 1:
RATE and TIME are RECIPROCALS.
If Rachel were to travel at 3/2 her actual rate, the trip would take 2/3 her actual time.
This relationship will hold true for ANY RATE.
Implication:
The rate can be any value.
INSUFFICIENT.

Statement 2:
Test rates that are 20mph apart and that divide cleanly into d=120.
Look for a time difference of 1 hour.
10mph and 30mph --> 120/10 = 12 hours, 120/30 = 4 hours.
20mph and 40mph --> 120/20 = 6 hours, 120/40 = 3 hours.
40mph and 60mph --> 120/40 = 3 hours, 120/60 = 2 hours.
The option in red works.
Thus, the actual rate = 40mph.
SUFFICIENT.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by [email protected] » Thu May 21, 2015 3:18 pm
Hi aj_gmatwizard,

Since a couple of explanations have already been presented, I won't rehash any of that work here. Instead, I'm going to offer a bit more explanation as to why Fact 1 is insufficient. It's actually based on a "math truism", which in real simple terms is a "math fact that most people don't realize."

The Distance Formula is...

Distance = (Rate)(Time)

....and it's a formula that you'll likely use a couple of times on the Official GMAT (so it's worth knowing).

Fact 1 tells us that increasing the rate by 50% would lead to a time that is 2/3 of the original. Using the Distance Formula, we can prove that this occurs for ANY speed...

D = (R)(T)

Raising the Rate by 50% and decreasing the Time to 2/3 of the original time gives us...

(3/2)(R)(2/3)(T).

Since we're multiplying 'elements', we can put them in any order:

(3/2)(2/3)(R)(T)

(3/2)(2/3) = 6/6 = 1

So we have (1)(R)(T)

D = (R)(T)

In the end, the information in Fact 1 is NOT new information - it's a math fact when dealing with ANY speed and nothing more. Fact 1 is insufficient.

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Brent@GMATPrepNow » Fri May 22, 2015 9:34 am
aj_gmatwizard wrote:Rachel drove the 120 miles from A to B at a constant speed. What was this speed?

Statement #1: If she had driven 50% faster, her new time would have been 2/3 of her original time.
Statement #2: If she had driven 20 mph faster, she would have arrived an hour sooner.
Here's an algebraic solution for statement 2 that uses only 1 variable.

Target question: What was Rachel's speed?

Statement 1: If she had driven 50% faster, her new time would have been 2/3 of her original time.
Mitch has already done a great job (as usual) explaining why statement 1 is NOT SUFFICIENT, so I'll defer you to his solutions.

Statement 2: If she had driven 20 mph faster, she would have arrived an hour sooner.
Let's start with a "word equation"
When driving her regular speed, Rachel's trip time is 1 HOUR LONGER than her trip time when driving 20 mph faster.
So, let's write the following:
(Rachel's trip time at REGULAR speed) - (Rachel's trip time at FASTER speed) = 1 hour

From here, let's let R = her REGULAR speed
This means R + 20 = her FASTER speed

Since trip time = distance/speed, we can now write the following:
120/R - 120/(R+20) = 1 hour
Now solve the equation for R

Multiply both sides by (R)(R+20) to get: 120(R+20) - 120R = (R)(R+20)
Expand to get: 120R + 2400 - 120R = R² + 20R
Rearrange and simplify to get: R² + 20R - 2400 = 0
Factor: (R + 60)(R + 40) = 0
So, R = -60 or R = 40
Since Rachel's speed cannot be negative, it MUST be the case that R = 40
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = B

-------------------------------------------
Word problems are tricky for A LOT of students. One of the hardest steps is creating the corresponding equation(s). In many cases, I like to create a "WORD EQUATION" as an intermediary step.

Here's an article I wrote about this strategy: https://www.beatthegmat.com/mba/2014/09/ ... -equations

Here are a few questions where I've used a word equation:
- https://www.beatthegmat.com/insurance-t278612.html
- https://www.beatthegmat.com/equation-t107935.html
- https://www.beatthegmat.com/speed-distan ... 80473.html
- https://www.beatthegmat.com/stuck-with-m ... 63906.html
- https://www.beatthegmat.com/rate-distanc ... 21963.html
- https://www.beatthegmat.com/distance-wor ... 81078.html

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion