-
kamalakarthi
- Senior | Next Rank: 100 Posts
- Posts: 80
- Joined: Mon Jan 31, 2011 10:08 pm
- Followed by:2 members
Let's examine the EXTREME VALUES Of x and y and see what happens.If -4 < x < 7 and -6 < y < 3, which of the following specifies all the possible values of xy?
a. -42<xy<21
b. -42<xy<24
c. -28<xy<18
d. -24<xy<21
e. -24<xy<24
If we want to MINIMIZE the value of xy, we need to examine what happens when 1 EXTREME value is positive and 1 EXTREME value is negative.
case a: x = -4 and y = 3, in which case xy = -12
case b: x = 7 and y = -6, in which case xy = -42
Great, so xy is MINIMIZED when x = 7 and y = -6
Of course, we're told that x < 7 and y > -6, but that's fine. Basically, this means that xy > -42
At this point, we know that the correct answer must be either A or B.
Next, if we want to MAXIMIZE the value of xy, we need to examine what happens when both EXTREME values are positive or both are negative.
case c: x = -4 and y = -6, in which case xy = 24
case d: x = 7 and y = 3, in which case xy = 21
Great, so xy is MAXIMIZED when x = -4 and y = -6
Of course, we're told that x > -4 and y > -6, but that's fine. Basically, this means that xy < 24
So, as you can see, -42 < xy < 24
Answer: B
Cheers,
Brent



















