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exponents are killing me

Expert replies
by Wakka Wakka » Thu Jul 24, 2008 10:41 am
From a question in the MH GMAT practice test...from step 1 to step 2 we loose 5^13 which becomes (5-1)...can someone explane this to me please? THanks


1.) 5^12 – 6(5^13 – 5^12) =
2.) 5^12 – 6[5^12(5 – 1)] =
3.) 5^12 – 6(5^12)(4) =
4.) 5^12(1 – 24) =
5.) (-23)5^12.
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Source: — Problem Solving |

by Wakka Wakka » Thu Jul 24, 2008 10:45 am
I guess it couldn't hurt to post the question also...

A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^13, respectively, what is the value of A?
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by sudhir3127 » Thu Jul 24, 2008 10:47 am
5^12 – 6(5^13 – 5^12)

5^13 canbe written as 5^12*5 ( as the bases are same powers can be added)

hence it will be 5^12- 6( 5^12*5- 5^12)
5^12- 6.5^12( 5-1)
5^12 – 6(5^12)(4)

5^12(1 – 24)

hope its clear now.. let meknow if u still have a doubt..
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by Wakka Wakka » Thu Jul 24, 2008 10:56 am
I really appreciate it thank you...also thank for the quick reply.
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by Wakka Wakka » Thu Jul 24, 2008 1:05 pm
I was just going over the formula and I get that we can take 5^13 to 5^12*5, but how do we get one 5^12 to become 1?

Thanks
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by Wakka Wakka » Thu Jul 24, 2008 2:10 pm
Nevermind...haha, just saw it...really appreciate it though, THANKS!!!
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