Speed Problem

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Speed Problem

by soumya_165 » Sun Oct 07, 2012 12:46 pm
James and Andrea take a trip in Andrea's car. On the first leg of the trip, they drive 40 miles per hour to their destination. On the second leg, they turn around and return by the same route in 4 hours. How long do they spend driving on the first leg?

STATEMENT 1:

Their average speed for the entire trip is 35 miles per hour.

STATEMENT 2:

The distance to their destination is 110 miles.

a) Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not.
b) Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not.
c) Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient.
d) EITHER statement BY ITSELF is sufficient to answer the question.
e) Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.
Source: — Data Sufficiency |

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by zorroprateek » Sun Oct 07, 2012 1:01 pm
We know speed of the car for the first leg, if we get the distance as well we can calculate the time it took them to finish first leg.

STATEMENT 1:

Average speed of entire trip = total distance(leg1 +leg2)/total time(leg1+leg2). Total time is not known and therefore distance cannot be calculated.

STATEMENT 2:

Distance =110miles, speed=40 miles/hour therefore time =110/40 hour.

Answer should be B.

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by das.ashmita » Sun Oct 07, 2012 10:09 pm
Hi Somya
1. Their average speed for the entire trip is 35 miles per hour.
let the distance be d
total time = time(leg1) + time(leg2)
= (d/40) + 4
Avg Speed = total distance/ total time
35 = 2d/[(d/40) + 4]
We can get d from the eqn above. time(leg1) can be calculated as d/40

SUFF
2. The distance to their destination is 110 miles.
time(leg1) = 110/40

SUFF

Therefore ANS D

Hope it helps :)

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by Whitney Garner » Mon Oct 08, 2012 7:29 am
soumya_165 wrote:James and Andrea take a trip in Andrea's car. On the first leg of the trip, they drive 40 miles per hour to their destination. On the second leg, they turn around and return by the same route in 4 hours. How long do they spend driving on the first leg?

STATEMENT 1:

Their average speed for the entire trip is 35 miles per hour.

STATEMENT 2:

The distance to their destination is 110 miles.

a) Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not.
b) Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not.
c) Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient.
d) EITHER statement BY ITSELF is sufficient to answer the question.
e) Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.
Hi soumya_165!

I'm definitely with das.ashmita on this one, the answer should be D, but please be careful when you post or with the types of content you use - this question is not written correctly. Both statements DO give you an answer, BUT they give you different answers - A BIG GMAT NO-NO (and I tried several ways of re-writing the problem to see if I could correct the numbers and wasn't able to find anything that worked)!!

But, the math involved is actually very typically GMAT so definitely worth reviewing!

This question talks about Average Speed, a concept many GMAT Test Takers confuse so let's start there. The fundamental formula is:

Image

We can write Average Speed (A) in terms of the actual trip in the following way:

Image

For this question, we don't know the distance to or from the destination, BUT we know they are the same so we can call those simply D. We know that the time for the 2nd leg is 4 hours, but we only know the rate for the first leg. But that is okay - we can calculate Time using D=RT.
Image

So we're ready to plug this into the Average Rate formula & Simplify (the most important step of ANY DS problem):

Find common denominator to combine the denominator fractions:
Image
Simplify the division by multiplying by the reciprocal:
Image

Okay, so this simplified expression is the information the question is GIVING US. Now, what is the question ASKING us for??

"How long do they spend driving on the first leg?"
Well, we actually solved this to plug into the Average Speed Formula...
Image
So looks like all we really need to know is D!

That means I am REALLY liking the looks of Statement (2), so I'm going to start there:

Statement (2): "The distance to their destination is 110 miles."
This says that D=110, so
Image
SUFFICIENT - eliminate A, C, and E

Statement (1): "Their average speed for the entire trip is 35 miles per hour."
This says that A=35, so let's plug into that Average Speed formula from above, cross multiply, simplify and solve for D:
Image
**Notice that at any point in this equation we could have stopped and said "hey, this is a single equation with a single unknown, we should be able to solve this - but just to show the steps of simplification and the actual result (that is different from the D given in statement (2)), I went through the work.

Plug this in for our time:
Image
SUFFICIENT - the answer is D, BOTH are sufficient

Now just remember to always be careful of the sources where you find your study material - words to live by: "Bad Advice is FAR WORSE than no advice!!"

Hope this helps!
:)
Whit
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by GMATGuruNY » Mon Oct 08, 2012 2:05 pm
soumya_165 wrote:James and Andrea take a trip in Andrea's car. On the first leg of the trip, they drive 40 miles per hour to their destination. On the second leg, they turn around and return by the same route in 4 hours. How long do they spend driving on the first leg?

STATEMENT 1: Their average speed for the entire trip is 35 miles per hour.
In statement 1, we know the average speed for the FIRST LEG and the average speed for the ENTIRE TRIP.
With this information, we can determine the TIME RATIO for the two legs of the trip.
The time ratio will be the same REGARDLESS of the actual distance.
Thus, we can plug in ANY VALUE for the distance.

Let the distance for each leg = the LCM of 35 and 40 = 280 miles.
Time to travel the FIRST LEG at a rate of 40mph = d/r = 280/40 = 7 hours.
Time to travel BOTH LEGS at an average speed of 35mph = d/r = 560/35 = 16 hours.
Thus, the time for the SECOND LEG = 16-7 = 9 hours.
TIME RATIO = FIRST LEG : SECOND LEG = 7:9.

To determine the ACTUAL TIME for the first leg, we can set up a proportion.
Since the actual time for the second leg = 4 hours, we get:
7/9 = x/4
x = 28/9 hours.
SUFFICIENT.
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