BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

please help.. geometary

Expert replies
by AJWILL » Sat Aug 18, 2012 4:00 am
In the figure given below, square ABCD is inscribed in a circle.Point E is joined to D and C such that AE = EB. If the area of the triangle is 20 square units find the difference in area of the circle and the square.
Attachments
ShowImage.jpg
Join the discussion
Source: — Problem Solving |

by neelgandham » Sat Aug 18, 2012 5:16 am
Let the side of the square be A and the radius of the circle be C.
i.e. AB = BC = CD = DA = A and AC = 2*C
We also know that AC is the diagonal of the square ABCD.
i.e. AC = 2*C = √2 * A => C = A/√2
Area of the Triangle DEC = (1/2)*Base*Height = (1/2) * CD * BC = (1/2)*A*A = 20 Square units
i.e. A*A = 40, A = 2√10 .
Radius of the circle = C = A/√2 = 2√10/√2 = 2√5.

Area of the circle = pi*C*C = pi*2√5*2√5 = pi*20 square units.
Area of the square = A*A = A*A = 40 square units.
Difference is areas = pi*20 - 40
Last edited by neelgandham on Sat Aug 18, 2012 7:36 am, edited 1 time in total.
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Join the discussion

by GMATGuruNY » Sat Aug 18, 2012 6:52 am
AJWILL wrote:In the figure given below, square ABCD is inscribed in a circle.Point E is joined to D and C such that AE = EB. If the area of the triangle is 20 square units find the difference in area of the circle and the square.
Square:
The triangle and the square have the same base and height.
Since the area of a triangle = (1/2)bh and the area of a parallelogram = bh, the square is twice the size of the triangle.
Since the area of the triangle = 20, the area of the square = 2*20 = 40.

Circle:
The diameter of the circle is the diagonal of the square.
The diagonal of a square = s√2.
Since the area of the square is 40, s = √40 and d = (√40)(√2) = 4√5.
Thus, the radius of the circle = 2√5.
Area = �r² = �(2√5)² = 20�.

Circle - square = 20� - 40.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by pemdas » Sat Aug 18, 2012 2:32 pm
there are 3 triangles which one's area is 20

anyways, it takes only 5 seconds to figure that area of square a^2 is the total of three triangles and the larger triangle is two times the area of each of the other two smaller triangles.

depending on the triangle's area (not specified here) we can get a^2=40 or a^2=80. Then a=sqrt(40) or sqrt(80). The radius of circle, R, would be 1/2*sqrt(2)*side of square ==> R=sqrt(2*40)/2 or sqrt(2*80)/2. The area of circle would be Pi*80/4 or Pi*160/4 ==> Pi*20 or Pi*40

We may get two answers depending on the triangle (not specified here): Pi*20-40 or Pi*40-80
Success doesn't come overnight!
Join the discussion