inequalities

[Carlo75]

If w + x <0, is w - y >0?


(1) x+y < 0

(2) y < x < w

please explanations ...

[Carlo75]

the question is: is w - y > 0 ?

[Ian Stewart]

If w + x <0>0?


(1) x+y < 0

(2) y < x < y

please explanations ...

Hi Carlo,

Could you type the question again? Statement 2, of course, doesn't make much sense as it's written! I've just learned myself that using < and > can call up html tags, so you should click the 'Disable HTML in this post' button before submitting to make things read correctly.

[netigen]

A is insufficient

Given w + x <0

w +x - y < -y
w - y < -(x+y)

since we know that x+y<0

so, w-y < z where z is +ve number

B has been incorrectly posted.

[Carlo75]

OA is B.

[Carlo75]

You have shown that (w-y) < -(x+y) because x +y < 0 the answer, is w - y >0 ?, could be YES so it is insufficient.

[sasi78]

As per question,
w+x<0> w+x-y<y> w-y<-(x+y).

Stem1: x+y<0> w-y <x>0. But we can not say w-y is <or> 0. Hence, this is not sufficient.

Stem2: y<x<w> Add -y to all, 0<x-y<w> w-y >0. Hence, this is sufficient.

So, answer is B.

[sasi78]

There was a formatting problem in my earlier reply. pl refer this.

As per question,
w+x<0. this can be writen as (w+x-y)<y then, (w-y)<-(x+y).

Stem1: x+y<0. So (w-y)<x> 0. But we can't say (w-y) is <or> 0. Hence, this is not sufficient.

Stem2: y<x<w. Add -y to all, 0<(x-y)<w>0. Hence, this is sufficient.

So, answer is B.