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inequalities

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by Carlo75 » Fri Jun 06, 2008 7:59 am
If w + x <0, is w - y >0?


(1) x+y < 0

(2) y < x < w

please explanations ...
Last edited by Carlo75 on Fri Jun 06, 2008 9:59 am, edited 2 times in total.
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Source: — Data Sufficiency |
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by Carlo75 » Fri Jun 06, 2008 8:05 am
the question is: is w - y > 0 ?
Last edited by Carlo75 on Fri Jun 06, 2008 9:41 am, edited 1 time in total.
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Re: inequalities

by Ian Stewart » Fri Jun 06, 2008 9:18 am
Carlo75 wrote:If w + x <0>0?


(1) x+y < 0

(2) y < x < y

please explanations ...
Hi Carlo,

Could you type the question again? Statement 2, of course, doesn't make much sense as it's written! I've just learned myself that using < and > can call up html tags, so you should click the 'Disable HTML in this post' button before submitting to make things read correctly.
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by netigen » Fri Jun 06, 2008 9:55 am
A is insufficient

Given w + x <0

w +x - y < -y
w - y < -(x+y)

since we know that x+y<0

so, w-y < z where z is +ve number

B has been incorrectly posted.
Last edited by netigen on Fri Jun 06, 2008 10:15 am, edited 1 time in total.
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by Carlo75 » Fri Jun 06, 2008 10:00 am
OA is B.
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by Carlo75 » Fri Jun 06, 2008 10:09 am
You have shown that (w-y) < -(x+y) because x +y < 0 the answer, is w - y >0 ?, could be YES so it is insufficient.
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by sasi78 » Sat Jun 07, 2008 9:16 am
As per question,
w+x<0> w+x-y<y> w-y<-(x+y).

Stem1: x+y<0> w-y <x>0. But we can not say w-y is <or> 0. Hence, this is not sufficient.

Stem2: y<x<w> Add -y to all, 0<x-y<w> w-y >0. Hence, this is sufficient.

So, answer is B.
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by sasi78 » Sat Jun 07, 2008 9:23 am
There was a formatting problem in my earlier reply. pl refer this.

As per question,
w+x<0. this can be writen as (w+x-y)<y then, (w-y)<-(x+y).

Stem1: x+y<0. So (w-y)<x> 0. But we can't say (w-y) is <or> 0. Hence, this is not sufficient.

Stem2: y<x<w. Add -y to all, 0<(x-y)<w>0. Hence, this is sufficient.

So, answer is B.
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