Another remainder problem

[fangtray]

If a certain positive integer is divided by 9, the remainder is 3. What is the remainder when the integer is divided by 5?
1. If the integer is divided by 45, the remainder is 30
2. The integer is divisible by 2

[transfer9858]

I would say A. Any number that comes out to a multiple of 45 plus 30 will end in a 5 or a 0- making the remainder 0. 2- An example can be either 48 or 21 which would give you two different remainders when divided by 5.

[karthikgmat]

A is correct?

[fangtray]

a is correct

[neelgandham]

my $0.02

If a certain positive integer is divided by 9, the remainder is 3. What is the remainder when the integer is divided by 5? i.e. the positive integer K is of the form (9*x)+3, where x is a non negative integer. The question can be rephrased to, 'If Integer K = (9*x)+3(where x is a non negative integer). What is the remainder when K is divided by 5?'

1. If the integer is divided by 45, the remainder is 30

K = (45*y)+30, where Y is a non-negative integer.
K = 5 * ((9*y)+6) = 5 * Positive Integer. If K is a multiple of 5, then 0 is the remainder when it is divided by 5.

Statement 1 is sufficient to answer the question!

2. The integer is divisible by 2

K = (9*x)+3 = 2*L(Where L is a positive Integer)
If x = 1, K = 12 (=2*L, where L = 6). K/5 = 12/5, remainder = 2
If x = 3, K = 30 (=2*L, where L =15). K/5 = 30/5, remainder = 0
Oops! Two different answers.

Statement 2 is insufficient to answer the question!