BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

number properties

Expert replies
Source: — Data Sufficiency |

by shankar.ashwin » Fri Jan 27, 2012 7:31 pm
(1) The only value which could satisfy this is 2^0 = 1 and 2^1 =2 and 2-1=1. Hence we can say K=2 - Sufficient

(2) Given K and N are integers, any (integer)^(integer) = integer. This statement is faulty and can never hold true.

A IMO
Join the discussion

by pemdas » Sat Jan 28, 2012 2:50 pm
@shankar, any integer^integer is not always integer
example:
2 is integer
-2 is integer
2^(-2)=1/4 non-integer

the condition doesnt' suggest K and N are the elements of set S either

To start the question says S is a set and S is the sum [spoiler]/assumption made is that S can be only the sum of elements in a set S/[/spoiler] of elements equal to K^N, where K and N are integers

st(1) implies a difference between two numbers. Can be any two numbers with any values, hence Insuff
st(2) suggests some number, a has restriction 1/4<a<1. Nothing more about numbers in S, Insuff
combining st(1&2): b-a or a-b equals 1. Since we are not told explicitly positive or negative integers, we may consider both a-b or b-a
Case 1) a-b=1 and 1/4<a<1, a=b+1, 1/4-1<b<1-1 OR -3/4<b<0
a+b>-3/4+1/4, a+b>-1/2
a+b<0+1, a+b<1. Thus -1/2<a+b<0 which is possible for several values K=-4, N=-1, K^N=-1/4 also K=-3, N=-1, K^N=-1/3

we don't need to test b-a=1 as there are too many choices already and this is Insuff

e
shankar.ashwin wrote:(1) The only value which could satisfy this is 2^0 = 1 and 2^1 =2 and 2-1=1. Hence we can say K=2 - Sufficient

(2) Given K and N are integers, any (integer)^(integer) = integer. This statement is faulty and can never hold true.

A IMO
Success doesn't come overnight!
Join the discussion

by neelgandham » Sat Jan 28, 2012 3:46 pm
pemdas wrote: To start the question says S is a set and S is the sum of elements equal to K^N, where K and N are integers
where is it mentioned in the question that S = Sum sum of elements equal to K^N ??
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Join the discussion

by rijul007 » Sat Jan 28, 2012 8:23 pm
shankar.ashwin wrote: (2) Given K and N are integers, any (integer)^(integer) = integer. This statement is faulty and can never hold true.
Are you sure?

coz 2^(-2) = 1/4

where both 2 and -2 are integers
Join the discussion

by rijul007 » Sat Jan 28, 2012 8:32 pm
sud21 wrote:K,N are integers. S is a set, and S=K^N. K=?
1). The difference between two numbers in S is 1
2). One of the numbers in S is more than 1/4 and less than 1
St(1)The difference between two numbers in S is 1

This can be true only for K=2
K^0 = 1
K^1 = 2
The differece is 1
SUFFICIENT

St(2)One of the numbers in S is more than 1/4 and less than 1

K=2
K^(-1) = 1/2
1/4 < 1/2 < 1

K=3
K^(-1) = 1/3
1/4 < 1/3 < 1

NOT SUFFICIENT

Option A
Join the discussion

by pemdas » Sun Jan 29, 2012 10:04 am
what does S=K^N stand for then? is it function of something else?
neelgandham wrote:
pemdas wrote: To start the question says S is a set and S is the sum of elements equal to K^N, where K and N are integers
where is it mentioned in the question that S = Sum sum of elements equal to K^N ??
Success doesn't come overnight!
Join the discussion

by neelgandham » Sun Jan 29, 2012 10:11 am
pemdas wrote:what does S=K^N stand for then? is it function of something else?
I am sorry mate, I am not really sure what it is. I just wanted to know if 'S = Sum of all integers' is an assumption or If I missed a thing or two in interpreting the question.

What I think it is :
S=K^N, for a constant K and variable N(e.g, K = 2, N={set of all integers))
S={.......2^-2, 2^-1, 2^0, 2^1, 2^2,......}
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Join the discussion

by shankar.ashwin » Wed Feb 01, 2012 11:21 pm
Oops sorry guys... Forgot to include -ve numbers..

Thanks for pointing out pemdas,rijul007 and Neel.. You guys the best :)

Though I guess A remains the answer..
Join the discussion