BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Length of a Triangle leg

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 11
Joined: Thu Jul 15, 2010 12:08 pm
by joconnor » Mon Dec 19, 2011 6:22 am
A certain right triangle has sides of length x, y, z where x<y<z. Area of tri is 1. Which indicates all the possible values of y?

y > sq rt 2

sq rt 3 / 2 < y < sq rt 2

sq rt 2 / 3 < y < sq rt 3 / 2

sqrt3 / 4 < y < sqrt2 / 3

y < sqrt3 / 4

thanks!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 385
Joined: Fri Sep 23, 2011 9:02 pmFollowed by: 6 members
Thanked: 62 times

by user123321 » Mon Dec 19, 2011 6:52 am
joconnor wrote:A certain right triangle has sides of length x, y, z where x<y<z. Area of tri is 1. Which indicates all the possible values of y?

y > sq rt 2

sq rt 3 / 2 < y < sq rt 2

sq rt 2 / 3 < y < sq rt 3 / 2

sqrt3 / 4 < y < sqrt2 / 3

y < sqrt3 / 4

thanks!
[spoiler]Is it A?[/spoiler]

in a right angled triangle, the area with above conditions is 1/2 * x * y
=> xy/2 = 1 (from given)
xy = 2
since x<y
y should be atleast greater than sqrt(2) to follow that condition.

user123321
Just started my preparation :D
Want to do it right the first time.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Community Manager
Posts: 1060
Joined: Fri May 13, 2011 6:46 amFollowed by: 52 members
Location: Utrecht, The Netherlands
Thanked: 318 times

by neelgandham » Mon Dec 19, 2011 6:56 am
A certain right triangle has sides of length x, y, z where x<y<z. Area of tri is 1. Which indicates all the possible values of y?.

Since x<y<z and length of Hypotenuse > length of the side(any side), we know that z is the length of the hypotenuse.
Area of triangle = 1/2 * base * height = 1/2 (Side X) * (Side Y) = (1/2)*x*y = 1 Implies xy = 2 and x = 2/y

From the question x<y.
Implies 2/y<y
Implies y-(2/y) > 0
Implies (y^2-2)/y > 0
Implies (y-√2)(y+√2)/y > 0
Checkpoints here are at y = √2, -√2 and 0
Since y is length of a side of a triangle, y > 0, so we need not check for y < 0
Condition 1
0<y<√2
(y-√2)(y+√2)/y < 0, doesn't satisfy the inequality.
Condition 2
y>√2
(y-√2)(y+√2)/y > 0, satisfies the inequality.

IMO option A
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 11
Joined: Thu Jul 15, 2010 12:08 pm

by joconnor » Mon Dec 19, 2011 7:33 am
answer is a

thanks!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Mon Dec 19, 2011 7:42 am
joconnor wrote:A certain right triangle has sides of length x, y, z where x<y<z. Area of tri is 1. Which indicates all the possible values of y?
y > sq rt 2
sq rt 3 / 2 < y < sq rt 2
sq rt 2 / 3 < y < sq rt 3 / 2
sqrt3 / 4 < y < sqrt2 / 3
y < sqrt3 / 4
thanks!
A quick way to solve this question is to recognize that the area of 1 has no effect on limiting the maximum length of y.

As the other two posts suggest, we can see that z is the length of the hypotenuse, and y is the longer of the two legs of the right triangle.
If the area is 1, then xy/2 = 1 with means xy=2
Given this, we could have x=0.1 and y=20, or we could have x=0.001 and y=2000, and so on.

As you can see, we can make y as long as we wish.
As such, we can eliminate answer choices B, C, D and E since they all limit the value of y.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1