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positive integer

by GmatKiss » Tue Nov 01, 2011 12:05 am
When positive integer x is divided by positive integer y,the remainder is 9. If x/y= 96.12, what is the value of y ?

(A) 96
(B) 75
(C) 48
(D) 25
(E) 12

IMO:[spoiler] B/D, as it ends with 5, how to proceed from here?[/spoiler]
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by Anurag@Gurome » Tue Nov 01, 2011 12:10 am
GmatKiss wrote:When positive integer x is divided by positive integer y,the remainder is 9. If x/y= 96.12, what is the value of y ?
x = (ky + 9) for some integer k
and x = 96.12y = 96y + 0.12y

Comparing the above two equations, 0.12y = 9 ---> y = 9/0.12 = 75

The correct answer is B.
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by shankar.ashwin » Tue Nov 01, 2011 12:19 am
You may also see Whitney's approach which I really like.
https://www.beatthegmat.com/number-prope ... tml#415002
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by GMATGuruNY » Tue Nov 01, 2011 2:09 am
Here's another approach:

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by vaibhavgupta » Wed Nov 02, 2011 2:13 pm
GmatKiss wrote:When positive integer x is divided by positive integer y,the remainder is 9. If x/y= 96.12, what is the value of y ?

(A) 96
(B) 75
(C) 48
(D) 25
(E) 12

IMO:[spoiler] B/D, as it ends with 5, how to proceed from here?[/spoiler]
Simple 0.12y=9
hence B is the answer!
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/
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