Still working on inequalities

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Still working on inequalities

by knight247 » Tue Aug 23, 2011 10:54 am
If x y and z are positive integers, is (x/y)^z>1?
(1)y-x=2
(2)z>1

Don't have an OA. Here is my take on it
(1)Statement 1 tells us that y>x and hence 0<x/y<1. We know that z>0. Hence irrespective of the +ve value of z the value of (x/y)^z will always be betn 0 and 1
(2)Statement 2 say z>1. By itself, no relation ship betn x and y is established hence insufficient.

Hence A. Is my logic correct?
Source: — Data Sufficiency |

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by force5 » Tue Aug 23, 2011 11:35 am
Yes A should this be. from statement 1 x/y will always be a fraction.