DS- Parallegram, Kites, rhombus, quads etc Q2

[kaps786]

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD

OA follows....





OA D


Same main theme as my previous post, if you could help explain what properties must we know of the different shape types...and explain in this context

[Anurag@Gurome]

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.
(2) AB = BC = CD = AD

I suggest you to go through the various properties of these shapes and their explanations. Both of the statements are well known properties of rhombus. So both of them are individually sufficient to conclude that ABCD is a rhombus.

Using statement 1 we can easily derive the statement 2 which is the definition of rhombus.

[bblast]

Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.
(2) AB = BC = CD = AD

I suggest you to go through the various properties of these shapes and their explanations. Both of the statements are well known properties of rhombus. So both of them are individually sufficient to conclude that ABCD is a rhombus.

Using statement 1 we can easily derive the statement 2 which is the definition of rhombus.

Hi Anurag,
To make a rhombus a square can a DS statement say : (all 4 sides are equal since rhombus)
1 >The diagonals bisect the opposite angles