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3 consecutives

Expert replies
Source: — Problem Solving |

by Kay_LAL » Wed Jul 27, 2011 5:03 am
1*2*3=6

hence its A....just my view.
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by beatthegmat.garry » Wed Jul 27, 2011 6:57 am
Among any 3 consecutive integers you will find either 2 numbers one of them a multiple of 2 and the other a multiple of 3 or one number which is multiple of 6. Hence when you multiple 3 consecutive numbers the product will be a multiple of 6.

From the above list 116 is the only number which is not a multiple of 6.
Hence the answer is C.

Thanks !
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by MarkMeier20 » Wed Jul 27, 2011 7:30 am
If p is a positive integer and
r = p(p + 1) (p + 2), then which of the
following could not be a value of r?
A. 6
B. 36
C. 116
D. 156
E. 180
B,C,D and E could not be a value of r. 6 could be a value of r.
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by Kay_LAL » Wed Jul 27, 2011 7:43 am
Kay_LAL wrote:1*2*3=6

hence its A....just my view.
Sorry... I didnt notice that 'it could not be '
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by finance » Wed Jul 27, 2011 11:51 am
beatthegmat.garry wrote:Among any 3 consecutive integers you will find either 2 numbers one of them a multiple of 2 and the other a multiple of 3 or one number which is multiple of 6. Hence when you multiple 3 consecutive numbers the product will be a multiple of 6.

From the above list 116 is the only number which is not a multiple of 6.
Hence the answer is C.

Thanks !
Hi!

Thank you for your explanation. Can you please tell me what are the three consecutive numbers that give 36 when multiplied.
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