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Probability

by SwatiDenre » Mon Jun 13, 2011 5:16 pm
How many 5 digit numbers can be formed using the digits 0,2,3,4and5 when repetition is allowed such that the number formed is divisible by 2 or 5 or both?

A. 100
B. 125
C. 3125
D. 1500
E. 125


Ans- 1500

Solution?
Thanks in advance.
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by MBA.Aspirant » Mon Jun 13, 2011 6:41 pm
I'm getting 2000 for this one!?

1st digit can be decided in 4 ways (2,3,4,5)
2nd in 5 ways (0,2,3,4,5)
3rd 5 ways
4th 5 ways
5th 4 ways to be divisible by 2 or 5 or both (0,2,4,5)

4*5*5*5*4 = 2000 ways
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by Ashley@VeritasPrep » Mon Jun 13, 2011 7:14 pm
Me too... please verify the problem! And do you trust the source to be without error, if this is indeed what the problem says?

Thanks!
Ashley Newman-Owens
GMAT Instructor
Veritas Prep

Post helpful? Mosey your cursor on over to that Thank button and click, please! I will bake you an imaginary cake.
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by SwatiDenre » Tue Jun 14, 2011 7:28 am
yah even i got the same answer i.e 2000. SO i thought of posting the question in case if i am wrong. Maybe the answer choices provided are wrong.
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