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MBA.Aspirant
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IMO B
given that
-2 < n <= 3
so if you put the all values of n there. then the equation will be satisfied.
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jainnikhil02
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jainnikhil02
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and please make sure you are using n (-1, 0, 1, 2, 3 ) Only. -2 is the only value that is eliminating the A option.
Nikhil K Jain
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Shankenstein
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The answer is A.
suppose we take n as -1 then,
1) 4-(-1) @ 6 => 5 < 6.
2) 4-(-1) @ 5 => 5 = 5.
then we take 3,
1) 4-(3) @ 6 => 1<6.
2) 4-(3) @ 5 => 1<5.
All the values between -2 and 3 including 3 will satisfy these two equations with @ replaced with <=.
suppose we take n as -1 then,
1) 4-(-1) @ 6 => 5 < 6.
2) 4-(-1) @ 5 => 5 = 5.
then we take 3,
1) 4-(3) @ 6 => 1<6.
2) 4-(3) @ 5 => 1<5.
All the values between -2 and 3 including 3 will satisfy these two equations with @ replaced with <=.
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MBA.Aspirant
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Frankenstein
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hi,MBA.Aspirant wrote:4-n @ 6
4-n @ 5
Which of the following symbols should be substituted for @ to make both of the statements above true for all integers n such that -2 < n <= 3?
a. <=
b. <
c. =
d. >
e. >=
Is the answer B)< ?
-2<n<=3.
So, -3 <= -n <2
i.e. 4-3 <= 4-n < 4+2.
Hence, 1<=4-n<6
i.e. 1>=4-n<=5.
Hence, A
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cans
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IMO A
-2<n<=3
when n=-1,4-n = 5
when n=3,4-n=1
Thus 4-n<=6
4-n<=5
-2<n<=3
when n=-1,4-n = 5
when n=3,4-n=1
Thus 4-n<=6
4-n<=5
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