XY>1?

[mariah]

XY>1?
1). X^Y=1
2). Y=-1

[Rahul@gurome]

XY>1?
1). X^Y=1
2). Y=-1

Statement 1: X^Y = 1
Implies either (X = 1, Y = Any number) or (X = Any number except zero, Y = 0)
Thus, XY may be < 1 or > 1 or equal to 0.

Not sufficient.

Statement 2: Y = -1
X can be anything.

Not sufficient.

1 & 2 Together: Only possible values of X and Y are X = 1 and Y = -1. Thus XY = -1 < 1

Sufficient.

The correct answer is C.

[beat_gmat_09]

Y = -1
Only possible value of X is 1.
Thus, XY = -1 < 1

Sufficient.

Y = -1, how come value of X is 1. X can be anything, if X = 1 XY< 1, if X = -2 XY>1
Value of X is not given in B.

[Rahul@gurome]

Y = -1, how come value of X is 1. X can be anything

Thanks.
I made a terrible mistake!

[nubu]

X^Y = 1 & Y= -1
=> X^(-1) = 1 <=> 1/(X^1) = 1 <=> X^1 = 1 <=> X = 1

=> XY = -1 < 1

Pick C

[hitesht]

Hi Rahul, how can the value of X be anything?
considering 1 & 2 together, if X=2 and Y=-1
X^Y = 1/2
So X can be only 1.

[Rahul@gurome]

Hi Rahul, how can the value of X be anything?
considering 1 & 2 together, if X=2 and Y=-1
X^Y = 1/2
So X can be only 1.

That was a typo.
Edited.

[gdk800]

I think Rahul's first post says it all. In the first go even i could also come up with X=1 only considering both statements together. Thus OA has to be C with X = 1 and Y = -1.