(A) 55
(B) 60
(C) 70
(D) 75
(E) 90
![Image](https://b.imagehost.org/0444/triangle.jpg)
E is incorrect.goyalsau wrote:I think it should be E,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
What is the OA,beat_gmat_09 wrote:E is incorrect.goyalsau wrote:I think it should be E,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
OA is D. I dont have explanation.goyalsau wrote:What is the OA,beat_gmat_09 wrote:E is incorrect.goyalsau wrote:I think it should be E,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
Do you have the explanation...
IF you have please post it then,
This is a very hard problem to solve without using trigonometry. The trick is to draw a 30:60:90 triangle and notice all the isosceles triangles that are created.beat_gmat_09 wrote:In the figure to the right, point D divides side BC of triangle ABC into segments BD and DC of lengths 1 and 2 units respectively. Given that Angle ADC = 60 and Angle ABD = 45, what is the measure of angle x? (Note: Figure is not drawn to scale.)
(A) 55
(B) 60
(C) 70
(D) 75
(E) 90