(A) 55
(B) 60
(C) 70
(D) 75
(E) 90
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Measure of angle x
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beat_gmat_09
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In the figure to the right, point D divides side BC of triangle ABC into segments BD and DC of lengths 1 and 2 units respectively. Given that Angle ADC = 60 and Angle ABD = 45, what is the measure of angle x? (Note: Figure is not drawn to scale.)
(A) 55
(B) 60
(C) 70
(D) 75
(E) 90
(A) 55
(B) 60
(C) 70
(D) 75
(E) 90
-
goyalsau
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I think it should be E,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
Saurabh Goyal
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beat_gmat_09
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E is incorrect.goyalsau wrote:I think it should be E,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
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goyalsau
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What is the OA,beat_gmat_09 wrote:E is incorrect.goyalsau wrote:I think it should be E,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
Do you have the explanation...
IF you have please post it then,
Saurabh Goyal
[email protected]
-------------------------
EveryBody Wants to Win But Nobody wants to prepare for Win.
[email protected]
-------------------------
EveryBody Wants to Win But Nobody wants to prepare for Win.
-
beat_gmat_09
- Master | Next Rank: 500 Posts
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OA is D. I dont have explanation.goyalsau wrote:What is the OA,beat_gmat_09 wrote:E is incorrect.goyalsau wrote:I think it should be E,
Angle ADC is the exterior angle of Traingle ADC,
Angle BAD is 15,
as the segment AD divides the line CB in the ratio of 1:2,
Angle BAD, must be half of Angle CAD,
by this relation, Angle DAC is 30 ,
we have two angles of a triangle so angle C must be 90,
Do you have the explanation...
IF you have please post it then,
Hope is the dream of a man awake
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GMATGuruNY
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This is a very hard problem to solve without using trigonometry. The trick is to draw a 30:60:90 triangle and notice all the isosceles triangles that are created.beat_gmat_09 wrote:In the figure to the right, point D divides side BC of triangle ABC into segments BD and DC of lengths 1 and 2 units respectively. Given that Angle ADC = 60 and Angle ABD = 45, what is the measure of angle x? (Note: Figure is not drawn to scale.)
(A) 55
(B) 60
(C) 70
(D) 75
(E) 90
For one possible solution, please see the attachment.
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- BTG_angle_x.pdf
- (71.16 KiB) Downloaded 75 times
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I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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