GMAT Prep 1 PS 31

[starxx68]

I couldn't get this one. Please help.

[camitava]

starxx68,
Total population = 132,000 Cities = 11
So if equally distributed, each city would have = 12,000 population.
But now if 10% of population can vary in each city.
So minimum range of population that a city can have = (90/100 * 12000) = 10,800 and maximum = (110/100 * 12000) = 13200. So the minimum population that a city can have = 11000. IMO D.

[specialk1975]

You can back solve this one:

Take the 11,000

1) 132000 - 11000 = 121,000 "remaining population"
2) 121,000/ 10 (the remaining cities) = 12,100 (per city)
3) (12,100-11,000)/ 11,000 = 10%

*If you take the 10800 choice, you get 12% which is to high.

[Auzbee]

So minimum range of population that a city can have = (90/100 * 12000) = 10,800 and maximum = (110/100 * 12000) = 13200. So the minimum population that a city can have = 11000. IMO D.

Amitava,
In your explanation why did you choose 11000 and not 10900?

[camitava]

Hey Auzbee! U r right man. It should be 10900 but not 11000. A miss from y side. However thanks Auzbee for pointing out my mistake.