Gmat quest_post 2-explanations must

[raviagni]

1) Is |x|<1> x^2y^2?

(1) 14x^2 = 3

(2) y^2 = 1



A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.



6)The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?

(1) x > y

(2) < x – y



A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.



7)

If n is an integer and 100 < n <200, what is the value of n?

(1) is an odd integer.

(2) is an even integer.



A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and

[raviagni]

hi
i thought the same,that's why posted on the forum to cross-verify

[sankruth]

Please repost st 2 for #6. There seems to be mistake.

[camitava]

As already mentioned by sankruth and chiquito, raviagni pls post the correct version of the Qs. However for the Q-1, IMO C.
Because x^2 = 3/14 and y^2 = 1 So x^2y^2 = 3/14 < 1.
And as x^2 = 3/14 so x = sqrt(3/14) or -sqrt(3/14) - so |x| in any case < 1. So taking the options together, we can achieve to conclude. So IMO C.

[StarDust845]

You are supposed to post different questions in different posts.

Regards,
Calista.