gmat prep 2

This topic has expert replies
Source: — Problem Solving |

User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

by sanju09 » Mon Sep 20, 2010 3:04 am
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com

Senior | Next Rank: 100 Posts
Posts: 78
Joined: Mon Sep 20, 2010 12:51 am

by girishbtg » Mon Sep 20, 2010 3:42 am
sanju09 wrote:
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 am
Location: India
Thanked: 267 times
Followed by:80 members
GMAT Score:760

by sanju09 » Mon Sep 20, 2010 4:06 am
girishbtg wrote:
sanju09 wrote:
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, 180º - 4 x + x = 120º

Or, x = 20º. Hence, sufficient
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com

Senior | Next Rank: 100 Posts
Posts: 78
Joined: Mon Sep 20, 2010 12:51 am

by girishbtg » Mon Sep 20, 2010 4:14 am
sanju09 wrote:
girishbtg wrote:
sanju09 wrote:
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, 180º - 4 x + x = 120º

Or, x = 20º. Hence, sufficient

Great...!

Thanks!

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Mon Sep 20, 2010 4:18 am
girishbtg wrote:Image
When you want to see how the angles in a figure affect each other, plug in twice. The attached .pdf shows two sets of angle measurements that satisfy the requirements of the figure. In each case, we can see that COD:BAO = 3:1 and that BCO:BAO = 2:1.

Statement 1:
If COD = 60, then 60:BAO = 3:1, and BAO = 20. Sufficient.

Statement 2:
If BCO = 40, then 40:BAO = 2:1, and BAO = 20. Sufficient.

The correct answer is D.
Attachments
Relationships_between_angles.pdf
(36.41 KiB) Downloaded 89 times
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3