Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

gmat prep 2

Expert replies
Source: — Problem Solving |

by sanju09 » Mon Sep 20, 2010 3:04 am
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]
The mind is everything. What you think you become. –Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion

by girishbtg » Mon Sep 20, 2010 3:42 am
sanju09 wrote:
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!
Join the discussion

by sanju09 » Mon Sep 20, 2010 4:06 am
girishbtg wrote:
sanju09 wrote:
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, 180º - 4 x + x = 120º

Or, x = 20º. Hence, sufficient
The mind is everything. What you think you become. –Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion

by girishbtg » Mon Sep 20, 2010 4:14 am
sanju09 wrote:
girishbtg wrote:
sanju09 wrote:
girishbtg wrote:Image

We have AB = OC = OB = r, the radius of circle in question. What is ∠BAO?

≡ ∠BAO = ∠BOA = let x =?

∴ ∠CBO = ∠BCO = 2 x.

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, ∠COB + ∠BOA = 120º

Or, we have a linear in x, sufficient

[2] If ∠BCO = 2 x = 40º, then x = 20º, sufficient


[spoiler]D[/spoiler]

Thanks for Responding...

but still am not able to find out that how A ( i.e. eq 1 ) is sufficient in itself... Plz elaborate

Thanks!

[1] If ∠COD = 60º, then ∠COA = 120º

Or, ∠COB + ∠BOA = 120º

Or, 180º - 4 x + x = 120º

Or, x = 20º. Hence, sufficient

Great...!

Thanks!
Join the discussion

by GMATGuruNY » Mon Sep 20, 2010 4:18 am
girishbtg wrote:Image
When you want to see how the angles in a figure affect each other, plug in twice. The attached .pdf shows two sets of angle measurements that satisfy the requirements of the figure. In each case, we can see that COD:BAO = 3:1 and that BCO:BAO = 2:1.

Statement 1:
If COD = 60, then 60:BAO = 3:1, and BAO = 20. Sufficient.

Statement 2:
If BCO = 40, then 40:BAO = 2:1, and BAO = 20. Sufficient.

The correct answer is D.
You do not have the required permissions to view the files attached to this post.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion