mgmatds4

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Source: — Data Sufficiency |

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by stop@800 » Mon Oct 20, 2008 4:24 am
IMO C

solving the qn stem
(2-p)(2-q) = 0 ??

4 - 2 (p+q) + pq = 0???


A)
pq given but no infor for p+q

B)
p+q given but no infor for pq


A+B
can solve as both values given

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by stubbornp » Mon Oct 20, 2008 11:28 am
stop@800 wrote:IMO C

solving the qn stem
(2-p)(2-q) = 0 ??

4 - 2 (p+q) + pq = 0???


A)
pq given but no infor for p+q

B)
p+q given but no infor for pq


Awsome use of picking numbers strategy...tnx a lot buddy..


A+B
can solve as both values given

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by schumi_gmat » Mon Oct 20, 2008 12:31 pm
x^2 - x(p+q) + pq = y

from 1 and 2

To find x intercept y=0

x^2 +2x - 8 = 0
(x+4)(x-2)=0

x=-4 or x =2

HEnce E

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by stop@800 » Mon Oct 20, 2008 1:14 pm
schumi_gmat wrote:x^2 - x(p+q) + pq = y

from 1 and 2

To find x intercept y=0

x^2 +2x - 8 = 0
(x+4)(x-2)=0

x=-4 or x =2

HEnce E
We do not need to find x intercept, we just need to find that is particulra point valid or not.

The equation is quadratic so it can have two x intercepts.

Hope this helps!!

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by 4meonly » Fri Oct 24, 2008 11:11 am
Agree with stop@800
Answer is C - we can answer definetly NO - there is no point (2;0) on this function

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by jimmiejaz » Mon Oct 27, 2008 5:29 am
4meonly wrote:Agree with stop@800
Answer is C - we can answer definetly NO - there is no point (2;0) on this function
Dear 4meonly,
I think that the answer is a definite YES. coz when you solve the equation with the 2 values together, we get 0=0;

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by venmic » Sun Aug 15, 2010 10:01 am
the below ansers are C and E
I think it is a c because if you solve the values are 2 and -4 so yes it does satisy the equation
so answer should be C

any other explanations please
stubbornp wrote:please explain