First consider (1) alone.
Square both sides of the equation.
(x+1)^2 = 4*(x-1)^2.
Or x^2+2x+1 = 4x^2 - 8x + 4.
Or 3x^2 - 10x + 3 = 0.
Or (3x - 1)(x - 3) = 0.
Or x = 3 or x = 1/3.
We do not get unique value of x.
So (1) alone is not sufficient.
Next consider (2) alone.
It just implies x is not equal to 3.
But we cannot say whether lxl < 1 or not.
So (2) alone is not sufficient.
Next combine both the statements together and check.
From (1) we have x = 3 or x = 1/3.
Since x is not equal to 3 by (2), x = 1/3 and lxl = 1/3 which is < 1.
So the answer to the question is yes.
The correct answer is hence (C).
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
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