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[smclean23]

Is w greater than 1?


(1) w+2>0

(2) w^2>1



OA is........E

I thought.....C because w can be positive greater than 2 and suffice. Negative number greater than -2 does not suffice both statements......EXPERTS PLEASE ADVISE....

[acecoolan]

Firstly don't assume w to be a integer since its not mentioned.

So if u take w = -1.2

Statement 1
w + 2 = -1.2 + 2 = 0.8 > 0

Statement 2
w^2 = (-1.2)^2 = 1.44 > 1

So clearly w can be < 1.

Hence E)

[cramya]

Stm I

w > -2

INSUFF

Stmt II

|w| > 1

w> 1 or w < -1

INSUFF

Together

w> -2

w^2 > 1

Take w = -1.5 > -2 w^2 > 1 NO
Take w = 2 2>-2 w^2>1 YES

Choose E)

[vscid]

As usual with the GMAT trap, w could be a fraction as well as integer.
Clear E.

[vivek.kapoor83]

Stmt II

|w| > 1

w> 1 or w < -1

INSUFF

cramya,
i hv ques here.
w^2 >1
then w>1 is ok
and w>-1 but as per u, it wil be w <-1
howcm..cn u explain.

[cramya]

cramya,
i hv ques here.
w^2 >1
then w>1 is ok
and w>-1 but as per u, it wil be w <-1
howcm..cn u explain.

w^2 > 1

|w| > 1

case 1(w positive):

w > 1

case 2: (w negative)

-w > 1

Divide by -1 inequality reverses

w < -1

Hope this helps!

Regards,
CR

[logitech]

(1) w+2>0


-2-----------------------> INSUF


(2) w^2>1

<--------------- - 1 + 1 -----------------------> INSUF

Together

-2 ----- -1 + 1------------------------> It still can be between -2 and - 1

E

[iamcste]

(1) w+2>0


-2-----------------------> INSUF


(2) w^2>1

<--------------- - 1 + 1 -----------------------> INSUF

Together

-2 ----- -1 + 1------------------------> It still can be between -2 and - 1

E

yeah, its best to visualize inequalities on the number line, wherever possible

[TNgri]

I thought that answer would be B. The question is asking whether w greater than 1?
If we state that the w will be less than 1, it is an answer to the question. Is it not?

[[email protected]]

this question only fools you once. Then from here on you will always look for the integers at the top.

Nate

[ironsferri]

HI All!

still not sure why I get confused on the feasability of stmt 2.
It says x>1 and x<1. So x is >1, correct? If so stmts 2 should be correct.

Is this what I'm missing?? : stmt 2 is saying instead x>1 OR x<1

Thanks![/i]

[kvcpk]

HI All!

still not sure why I get confused on the feasability of stmt 2.
It says x>1 and x<1. So x is >1, correct? If so stmts 2 should be correct.

Is this what I'm missing?? : stmt 2 is saying instead x>1 OR x<1

Thanks![/i]

stm2 is saying x>1 OR x<-1

So we are not sure if the valuewould be >1

Hope this helps!!

[Testluv]

Hi ironsferri,

kvcpk is correct.

Whenever you have two inequalities that can't mutually coexist (ie, w can't be greater than 1 and less than -1 at the same time), then you have alternative inequalities rather than joint inequalities.

So, how can w^2 be greater than 1? Only if w^2 is greater than 1.

And w^2 will be greater than 1 when |w| is greater than 1. So, either w is greater than 1 OR less than -1. (It is very helpful to plot this out on the number line).