solutions of the equation

[sanju09]

The three solutions of the equation f (x) = 0 are -2, 0, and 3. Therefore, the three solutions of the equation f (x - 2) = 0 are
(A) - 4, -2, and 1
(B) -2, 0 and 3
(C) 4, 2, and 5
(D) 0, 2 and 5
(E) 2, 4, and 7

[liferocks]

three solutions of the equation f (x) = 0 are -2, 0, and 3 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x

so f(x-2)=(x)(x-2)(x-5)P(X-2)

So three solutions of f(x-2) is 0, 2 and 5
Ans option D

[sanju09]

three solutions of the equation f (x) = 0 are - 4, 8, and 11 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x

so f(x-2)=(x)(x-2)(x-5)P(X-2)

So three solutions of f(x-2) is 0, 2 and 5
Ans option D

this is called hangover

[liferocks]

three solutions of the equation f (x) = 0 are - 4, 8, and 11 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x

so f(x-2)=(x)(x-2)(x-5)P(X-2)

So three solutions of f(x-2) is 0, 2 and 5
Ans option D

this is called hangover

hmm...copy paste from ur other question solution..edited

[dkumar.83]

Hi All,

Shouldn't the answer be A?

[bharatishiv]

Ans is "A"

f(x) = 0 has solns. -2,0,3

x = -2, 0, 3

For f(x-2) = -4, -2, 1