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solutions of the equation

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by sanju09 » Wed May 19, 2010 4:42 am
The three solutions of the equation f (x) = 0 are -2, 0, and 3. Therefore, the three solutions of the equation f (x - 2) = 0 are
(A) - 4, -2, and 1
(B) -2, 0 and 3
(C) 4, 2, and 5
(D) 0, 2 and 5
(E) 2, 4, and 7
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by liferocks » Wed May 19, 2010 4:49 am
three solutions of the equation f (x) = 0 are -2, 0, and 3 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x

so f(x-2)=(x)(x-2)(x-5)P(X-2)

So three solutions of f(x-2) is 0, 2 and 5
Ans option D
Last edited by liferocks on Wed May 19, 2010 4:54 am, edited 1 time in total.
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by sanju09 » Wed May 19, 2010 4:52 am
liferocks wrote:three solutions of the equation f (x) = 0 are - 4, 8, and 11 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x

so f(x-2)=(x)(x-2)(x-5)P(X-2)

So three solutions of f(x-2) is 0, 2 and 5
Ans option D
this is called hangover
The mind is everything. What you think you become. -Lord Buddha



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by liferocks » Wed May 19, 2010 4:53 am
sanju09 wrote:
liferocks wrote:three solutions of the equation f (x) = 0 are - 4, 8, and 11 we can say
f(x)=(x+2)(x)(x-3)P(X)..where P(X) is a polynomial of x

so f(x-2)=(x)(x-2)(x-5)P(X-2)

So three solutions of f(x-2) is 0, 2 and 5
Ans option D
this is called hangover
hmm...copy paste from ur other question solution..edited :)
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by dkumar.83 » Wed May 19, 2010 7:31 am
Hi All,

Shouldn't the answer be A?
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by bharatishiv » Wed May 19, 2010 4:41 pm
Ans is "A"

f(x) = 0 has solns. -2,0,3

x = -2, 0, 3

For f(x-2) = -4, -2, 1
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