P problem

[pradeepkaushal9518]

Given that p is a positive even integer with a positive units digit, if the units digit of p3 minus the units digit of p2 is equal to 0, what is the units digit of p + 3?

i dont have OA

[eaakbari]

Asumming your question was p^3-p^2 and not 3p-2p

Since units of p^3 -P^2 = 0

Units digit of p^3 and p^2 is the same

It can be one of the following
2
4
6
8

As these are even and positive

Out of all only 6 satisfies condition.

Hence units p = 6
units p +3
= 9
IMO 9

[pradeepkaushal9518]

sir why not 10 which also satisfy the condition

10^3=1000
10^2=100
1000-100=900

that is main question i think?

[eaakbari]

sir why not 10 which also satisfy the condition

10^3=1000
10^2=100
1000-100=900

that is main question i think?

Kya Sir bula raha hain yaar,

Given that p is a positive even integer with a positive units digit

Since units digit is a positive integer, 0 is neither positive nor negative. Hence it cannot be 0.

HTH

[pradeepkaushal9518]

ok now it is clear. do i know you ?

[eaakbari]

ok now it is clear. do i know you ?

Well i guess not, unless you know Ebrahim Akbari.