BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Explanation for DS question

Expert replies
by nadib002 » Wed Mar 31, 2010 10:42 pm
Is p divisible by 168?

(1) p is divisible by 14
(2) p is divisible by 12

Could someone please explain an approach to answer this DS question without substituting numbers?

Thank you


P.S. I am not adding the answer choices since they are same for all the DS questions.
Join the discussion
Source: — Data Sufficiency |

by gmatmachoman » Wed Mar 31, 2010 10:50 pm
nadib002 wrote:Is p divisible by 168?

(1) p is divisible by 14
(2) p is divisible by 12

Could someone please explain an approach to answer this DS question without substituting numbers?

Thank you


P.S. I am not adding the answer choices since they are same for all the DS questions.
step 1: Find the factors of 168 ---->( 2 ,3,7)

Using St 1:

Factors of 14 :( 2,7)

What if the P is a multiple of 3???. SO factors of 14 won't divide P --St 1 is insufficient

Using st 2:

factors of 12 : (2,3)
What if p is a multiple of 7?? So factors of 12 wont divide P--St 2 is insufficient

Combining St1 & St2:
U an divide P as all three factors are included in the set!!

So C
Join the discussion

by ajith » Wed Mar 31, 2010 11:06 pm
nadib002 wrote:Is p divisible by 168?

(1) p is divisible by 14
(2) p is divisible by 12

Could someone please explain an approach to answer this DS question without substituting numbers?

Thank you


P.S. I am not adding the answer choices since they are same for all the DS questions.
Any number which has factors 4,3 and 7 will be divisible by 14 and 12

84 is smallest of such numbers and it is not divisible by 168

Hence E
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by gmatmachoman » Wed Mar 31, 2010 11:57 pm
@Ajith

If the question would have been : Is P divisible by 84??

Hope Both statements together will wrk rite??
Join the discussion

by eaakbari » Thu Apr 01, 2010 1:02 am
Stem
168 = 2^3 * 7 *3

Hence p will have to have all of the following factors to be divisible by 168

Statement one
14 = 2 * 7
Hence p is div by 2 and 7
But insuff

Statemnent two
2^2 * 3
Hnce p is div by 2^2 and 3
Insuff

Combining
we can say p is div by 2^2 and 3 and 7
But we need another factor of 2 to be div by 168

Hence insuff

Answer E
Join the discussion

by ajith » Thu Apr 01, 2010 1:42 am
gmatmachoman wrote:@Ajith

If the question would have been : Is P divisible by 84??

Hope Both statements together will wrk rite??
Yes it would have worked!

84 is the LCM of 12 and 14!
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by anoopprasad » Sat Apr 03, 2010 11:12 pm
168 = 14 * 12
So if p is divisible by 14 and 12 it is divisible by 188

Ans: C
Join the discussion

by ajith » Sat Apr 03, 2010 11:36 pm
anoopprasad wrote:168 = 14 * 12
So if p is divisible by 14 and 12 it is divisible by 188

Ans: C
what about 84?

or 252
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by thephoenix » Sun Apr 04, 2010 12:05 am
ans is E
clearly s1 and 2 are not suff
lcm of 12 and 14 is 84
combining bth minimum posssible no is 84 which is not div by 168 and rest all are
hence no conclusion and therefore insuff
Join the discussion